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Equilibrium constant for the reaction: ...

Equilibrium constant for the reaction:
`H_(2)(g) +I_(2) (g) hArr 2HI(g) is K_(c) = 50 at 25^(@)C`
The standard Gibbs free enegry change for the reaction will be:

A

`-6.964 kJ`

B

`-9.694 kJ`

C

`-4.964 kJ `

D

`-6.496 kJ`

Text Solution

Verified by Experts

`DeltaG^(Theta) =- 2.303 RT logK_(c)`
`=- 2.303 xx 8.314 xx 298 log = 50`
`=-9.694 kJ`
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