The heat of reaction for, `C_(10)H_(8)+12O_(2(g)) rarr 10CO_(2(g))+4H_(2)O_((l))` at constant volume is `-1228.2 kcal` at `25^(@)C`. Calculate the heat of reaction at constant pressure at `25^(@)C`.

Explanation

For `C_(10)H_(8)(s) +12O_(2)(g) rarr 10CO_(2)+4H_(1)O(l)`
Given `Deltan, 10-12 =- 2, DeltaU =- 1228.2 xx 10^(3) cal`,
`T = 298 K,R =2 cal`
`DeltaH = DeltaU +DeltanRT =- 1228.2 xx 10^(3) +(-2) xx2xx298`
`=- 1229393 cal =- 1229.392 kcal`