`500cm^(3)` of a sample of an ideal gas is compressed by an average pressure of `0.1 atm` of `250 cm^(3)`. During this process, `10J` of heat flows out to the surroundings. Calculate the change in internal enegry of the system.

Explanation

`p = 0.1 atm, DeltaV = 250 - 500 =- 250cm^(3)`
`w =- pDeltaV =- 0.10 xx (-0.25)`
`= 0.125L atm or = 0.25 xx 101.3 = 25.32J`
`DeltaU = q+w =- 10 +25.32 = 15.32J`