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The equilibrium constant for the reactio...

The equilibrium constant for the reaction:
`CH_(3)COOH(l) +C_(2)H_(5)OH(l) hArr CH_(3)COOC_(2)H_(5)(l)+H_(2)O(l)`
has been found to be equal to `4` at `25^(@)C`. Calculate the free energy change for the reaction.

Text Solution

Verified by Experts

`DeltaG^(Theta) =- 2.303 xx 8.314 xx 298 log 4`
`=- 3.435 kJ mol^(-1)`
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The equilibrium constant for the reaction: CH_(3)COOH(l) + C_(2)H_(5)OH(l) iff CH_(3)COOC_(2)H_(5)(l)+ H_(2)O(l) has been found to be equal to 4 at 25^(@)C . Calcuclate the free energy chnage for the reaction.

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The equilibrium constant for the reaction CH_(3)COOH+C_(2)H_(5)OH hArr CH_(3)COOC_(2)H_(5)+H_(2)O is 4.0 at 25^(@)C . Calculate the weight of ethyl acetate that will be obtained when 120g of acetic acid are reacted with 92 g of alcohol.

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