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Delta(f)H^(Theta) of hypothetical MgCI i...

`Delta_(f)H^(Theta)` of hypothetical `MgCI` is `-125 kJ mol^(-1)` and for `MgCI_(2)` is `-642 kJmol^(-1)`. The enthalpy of disporportionation of `MgCI is -49x`. Find the value of `x`.

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`2MgCI rarr Mg +MgCI_(2) DeltaH = ?`
`Mg(s) +1//2CI_(2)(g) rarr MgCI DeltaH_(1) =- 125 kJ mol^(-1)`
`Mg(s) +CI_(2)(g) rarr MgCI DeltaH_(2) =- 642 kJ mol^(-1)`
`DeltaH = DeltaH_(2) - 2DeltaH_(1) =- 642 -(2 xx -125) =- 393 kJmol^(-1)`
`:. -49 x =- 392`
`x = 8`
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