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The equilibrium constant of the reaction...

The equilibrium constant of the reactions
`SO_(2)(g)+1/2 O_(2)(g)hArrSO_(3)(g)`
and `2SO_(2)(g)+O_(2)hArr2SO_(3)(g)`
are `K_(1)` and `K_(2)` respectively. The relationship between `K_(1)` and `K_(2)` is

A

`K_(1)=K_(2)`

B

`K_(2)^(2)=K_(1)`

C

`K_(1)^(2)=K_(2)`

D

`K_(2)=sqrt(K_(1))`

Text Solution

Verified by Experts

The correct Answer is:
C
`SO_(2)+1/2 O_(2) overset(K_(1))(hArr)SO_(3)`, `:. K_(1)=([SO_(3)])/([SO_(2)][O_(2)]^(1//2))`
`2SO_(2)+O_(2) overset(K_(1))(hArr)2SO_(3)`, `:. K_(2)=([SO_(3)]^(2))/([SO_(2)]^(2)[O_(2)])`
`:. K_(2)=K_(1)^(2)`
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