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When 4 mol of A is mixed with 4 mol of B...

When `4 mol` of `A` is mixed with `4 mol` of `B, 4 mol` of `C` and `D` are formed at equilibrium, according to the reaction
`A+B hArr C+D`
the equilibrium constant is

A

`sqrt(2)`

B

`2`

C

`1`

D

`4`

Text Solution

Verified by Experts

The correct Answer is:
C
`A+B hArr C+D`
According to the law of mass action
`K=([C][D])/([A][B])=(4xx4)/(4xx4)=1`
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