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For the reaction, A+2B hArr C, the expe...

For the reaction, `A+2B hArr C`, the expession for equilibrium constant is

A

`([A][B]^(2))/([C])`

B

`([A][B])/([C])`

C

`([C])/([A][B]^(2))`

D

`([C])/([2B][A])`

Text Solution

Verified by Experts

The correct Answer is:
C
`A+2B overset(K)(hArr) C`
According to law of mass action
`K=([C])/([A][B]^(2))`
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