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The equilibrium constant for the reactio...

The equilibrium constant for the reaction
`N_(2)+2O_(2)hArr2NO_(2)`
at a particular temperature is `100`. Write down the equilibrium law equations for the following reaction and determine the values of equilibrium constants.
`2NO_(2)hArrN_(2)+2O_(2)`
`NO_(2)hArr1//2N_(2)+O_(2)`

Text Solution

Verified by Experts

The equilibrium constant for the reaction
`N_(2)+2O_(2)hArr2NO_(2)`
`K_(c )=([NO_(2)]^(2))/([N_(2)][O_(2)]^(2))=100 ...(a)`
The equilidrium contabrium constant equation for reaction (i)
`K_(1)=([N_(2)][O_(2)]^(2))/([NO_(2)]^(2)) ..(b)`
this equation is reciprocal of equation (a)
So `K_(1)=1/K_(c )=1/100=1xx10^(-2)`
The equillibrium constant for reaction (ii)
`K_(2)=([N_(2)]^(1//2)[O_(2)])/([NO_(2)]) ...(c )`
Comparing equations `(b)` and `(c )`,
`K_(2)=sqrt(K_(1))=sqrt(10^(-2))=10^(-1)=0.1`
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