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A sample of CaCO(3)(s) is introduced int...

A sample of `CaCO_(3)(s)` is introduced into a sealed container of volume `0.654 L` and heated to `1000 K` until equilibrium is reached. The equilibrium constant for the reaction
`CaCO_(3)(s)hArrCaO(s)+CO_(2)(g),`
is `3.9xx10^(-2)` atm at this temperature. Calculate the mass of `CaO` present at equilibrium.

Text Solution

Verified by Experts

`CaCO_(3)(s)(s)hArrCaCO_(2)(g)`
`K_(p)=p_(CO_(2))=3.9xx10^(-2)`
Let the number of "moles" of `CO_(2)` be formed `=n`
`n=(p_(CO_(2))xxV)/(RT)=(3.9xx10^(-2)xx0.654)/(0.082xx1000)=3.11xx10^(-4) "mol"`
The amount of `CaO(s)` formed will also be
`=3.11xx10^(-4) "mol"`
Hence, the mass of `CaO` formed `=3.11xx10^(-4)xx56`
`=0.0174 g`
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