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For a system, a+2BhArrC , the equilibriu...

For a system, `a+2BhArrC` , the equilibrium comcentrations are `[A]=0.06, [B]=0.12`, and `[C]=0.216`. The `K_(c )` for the reaction is

A

`120`

B

`400`

C

`4xx10^(-3)`

D

`250`

Text Solution

Verified by Experts

The correct Answer is:
D
`A+2BhArrC`
`K=([C])/([A][B]^(2))rArr ((0.216))/((0.06)(0.012)^(2))=250`
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