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Two equilibrium ABhArrA^(o+)+B^(Θ) and ...

Two equilibrium `ABhArrA^(o+)+B^(Θ)` and `AB+B^(Θ)hArrAB_(2)^(Θ)` are simultaneously maintained in a solution with equilibrium constants `K_(1)` and `k_(2)`, respectively. Ratio of `[A^(o+)]` to `[AB_(2)^(Θ)]` in the solution is

A

Direclty proportional to `[B^(ɵ)]`

B

Inversely proportional to `[B^(ɵ)]`

C

Directly proportional to `[B^(ɵ)]^(2)`

D

Inversely proportional to `[B^(ɵ)]^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(1)=([AB^(o+)][B^(ɵ)])/([AB]), K_(2)=[AB_(2)^(ɵ)]//[AB][B^(ɵ)]`
or `[A^(o+)]=(K_(1)[AB])/([B^(ɵ)]),[AB_(2)^(ɵ)]=(K_(2)[AB][B^(ɵ)])/([AB_(2)^(ɵ)])`
`:.([A^(o+)])/([AB_(2)^(ɵ)]) prop1/([B^(ɵ)]^(2))`
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