Home
Class 11
CHEMISTRY
For the reaction PCl(5)(g)hArrPCl(3)(g...

For the reaction
`PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)`
Which of the following sketches may represent above equilibrium? Assume equilibrium can be achieved from either side and by taking any one or more components initially. Give `K_(c )` for the reaction `lt 2`?

A

B

C

D

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the equilibrium reaction: \[ PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g) \] We are given that the equilibrium constant \( K_c \) for this reaction is less than 2. We need to evaluate the provided sketches to determine which one represents this equilibrium condition. ### Step-by-Step Solution: ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Concept Applicationexercise 7.1|53 Videos

  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Ex 7.2|40 Videos

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    CENGAGE CHEMISTRY|Exercise Archives Subjective|15 Videos

  • CLASSIFICATION AND NOMENCLATURE OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY|Exercise Analytical and Descriptive Type|3 Videos

Similar Questions

Explore conceptually related problems

For the reaction, PCl_(5)(g)to PCl_(3)(g)+Cl_(2)(g)

For the reaction : PCl_(5) (g) rarrPCl_(3) (g) +Cl_(2)(g) :

For the gas phase reaction, PCl_(5)(g)rarrPCl_(3)(g)+CL_(2)(g) Which of the following conditions are correct?

For the reaction PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g) the forward reaction at constant temperature is favoured by

For the reaction PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g), the forward reaction at constant temperature favorrd by :

For the reaction PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) the forward reaction at constant temeprature is favoured by

For the reaction PCl_(5)(g) hArr PCl_(3)(g)+Cl__(2)(g) The forward reaction at constant temperature is favoured by

For the reaction, PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)) , the forward reaction at constant temperature is favoured by:

For PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g), write the expression of K_(c)