Home
Class 11
CHEMISTRY
Prove that the pressure necessary to obt...

Prove that the pressure necessary to obtain `50%` dissociation of `PCl_(5)` at `250^(@)C` is numerically three times of `K_(p)`.

Text Solution

AI Generated Solution

To prove that the pressure necessary to obtain 50% dissociation of \( PCl_5 \) at \( 250^\circ C \) is numerically three times \( K_p \), we can follow these steps: ### Step 1: Write the equilibrium reaction The dissociation of phosphorus pentachloride can be represented by the following equilibrium reaction: \[ PCl_5 (g) \rightleftharpoons PCl_3 (g) + Cl_2 (g) \] ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Concept Applicationexercise 7.1|53 Videos
  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Ex 7.2|40 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    CENGAGE CHEMISTRY|Exercise Archives Subjective|15 Videos
  • CLASSIFICATION AND NOMENCLATURE OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY|Exercise Analytical and Descriptive Type|3 Videos

Similar Questions

Explore conceptually related problems

Prove that the pressure necessary to obtain 50% dissociation of PCl_(5) at 500 K is numerically three times the value of K_(p) .

The equilibrium pressure necessary to obtain 50% dissociation of PCl_5 at 250^@C is numerically________of K_p .

At 300^@C the pressure necessary to obtained 80% dissociation of PCl_5 is numerically equal to

Total equilibrium pressure necessary to obtain 60% dissociation of PCl_5 is P at 500 K. The relation between equilibrium constant K_p and P is

At 200^(@)C PCl_(5) dissociates as follows : PCl_(5)(g0hArrPCl_(3)(g)+Cl_(2)(g) It was found that the equilibrium vapours are 62 times as heavy as hydreogen .The degree of dissociation of PCl_(5) at 200^(@)C is nearly :

The degree of dissociation of PCl_(5) will be more at ………. pressure.

The degree of dissociation of PCl_(5) decreases with increase in pressure.

PCl_(5) dissociation a closed container as : PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)) If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl_(5) is alpha , the partial pressure of PCl_(3) will be: