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When sulphur in the form of S(8) is heat...

When sulphur in the form of `S_(8)` is heated at `900 K`, the initial pressure of `1` atm falls by `10%` at equilibrium. This is because of conversion of some `S_(8)` to `S_(2)`. Find the value of equilibrium constant for this reaction.

Text Solution

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`S_(8)(g)hArr4S_(2)(g)`
`{:(Initila "mole",,1,,0),(At equilibrium,,1-x,,4x),(,,(1-0.10),,(4xx0.10)),(,,=0.9,,=0.40):}`
Applying the law of mass action,
`K_(p)=([p_(S_(2))]^(4))/([p_(S_(8))])=((0.4)^(4))/0.9=0.0256/0.9~~0.03a`
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