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For the reaction 2HI(g)hArrH(2)(g)+I(2...

For the reaction
`2HI(g)hArrH_(2)(g)+I_(2)(g)+I_(2)(g)`
The degree of dissociation `(alpha)` of `HI(g)` is related to equilibrium constant `K_(p)` by the expression
a. `(1+2sqrt(K_(p)))/2`, b. `sqrt((1+2K_(p))/2)`
c. `sqrt((2K_(p))/(1+2K_(p)))`, d. `(2sqrt(K_(p)))/(1+2sqrt(K_(p)))`

Text Solution

AI Generated Solution

To solve the problem, we need to relate the degree of dissociation (α) of HI to the equilibrium constant (Kp) for the reaction: \[ 2HI(g) \rightleftharpoons H_2(g) + I_2(g) + I_2(g) \] ### Step-by-Step Solution: 1. **Define the Reaction and Initial Conditions:** - The reaction starts with 2 moles of HI. At the beginning (t=0), we have: ...
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