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DeltaG^(ɵ) for 1/2 N(2)(g)+3/2H(2)(g) hA...

`DeltaG^(ɵ)` for `1/2 N_(2)(g)+3/2H_(2)(g) hArrNH_(3)(g)` is `-16.5 kJ mol^(-1)`. Find out `K_(p)` for the reaction at `25^(@)C`. Also report `K_(p)` and `DeltaG^(ɵ)` for `N_(2)(g)+3H_(2)(g) hArr2NH_(3)(g)` at `25^(@)C`.

Text Solution

Verified by Experts

`log K_(p)=-(DeltaG^(ɵ))/(2.303RT)=-((-16.5xx10^(3)))/(2.303xx8.314xx298)=2.8917`
`K_(p)=779.41`
`K_(p)` for reaction `N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g)` is equal to
`(779.41)^(2)=6.07xx10^(5)`
`DeltaG^(ɵ)=-2.303xx8.314xx298 log 6.07xx10^(5) J`
`=-32.998 kJ "mol"^(-1)`
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