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In the reaction equilibrium N(2)O(4) h...

In the reaction equilibrium
`N_(2)O_(4) hArr 2NO_(2)(g)`
When `5` mol of each is taken and the temperature is kept at `298 K`, the total pressure was found to be `20` bar.
Given : `Delta_(f)G_(n_(2)O_(4))^(ɵ)=100 kJ, Delta_(f)G_(NO_(2))^(ɵ)=50 KJ`
a. Find `DeltaG` of the reaction at `298 K`.
b. Find the direction of the reaction.

Text Solution

Verified by Experts

Reaction quotient `=([p_(NO_(2))]^(2))/([p_(N_(2)O_(4))])=100/10=10`
`DeltaG_("Reaction")^(ɵ)=2Delta_(f)G_(NO_(2))^(ɵ)-Delta_(f)G_(N_(2)O_(4))^(ɵ)`
`=2xx50-100=0`
we know, `DeltaG=DeltaG^(ɵ)-2.303RT log_(10) Q_(p)`
`=0-2.303xx8.314xx298 log 10`
`=-5705.8 J=-5.705 kJ`
Negative value shows that reaction will be in forward direction.
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