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The equilibrium constant K(p) for the ho...

The equilibrium constant `K_(p)` for the homogeneous reaction is `10^(-3)`. The standard Gibbs free energy change `DeltaG^(ɵ)` for the reaction at `27^(@)C ("using" R=2 cal K^(-1) mol^(-1))` is

A

Zero

B

`-1.8 kcal`

C

`-4.154 kal`

D

`+4.154 kcal`

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaG^(ɵ)=-RT "In" K_(p)`
`=-2xx300xxIn (10^(-3))`
`=+4.154 kcal`
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