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One mole of H(2) two moles of I(2) and t...

One mole of `H_(2)` two moles of `I_(2)` and three moles of `HI` are injected in one litre flask. What will be the concentration of `H_(2), I_(2)` and HI at equilibrium at `500^(@)C. K_(c )` for reaction `H_(2)+I_(2) hArr 2HI` is `45.9`.

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`{:(,H_(2),+,I_(2),hArr,2HI),("Initial moles",1,,2,,3),("moles at equilibrium",(1-x),,(2-x),,(3x+2x)):}`
`:. K_(c )=([HI]^(2))/([H_(2)][I_(2)])=([(3+2x)/V]^(2))/([(1-x)/(V)][(2-x)/(V)])`
`45.9=((3+2x)^(2))/((1-x)(2-x)), ( :' K_(c )=45.9)`
`45.9=(9+4x^(2)+12x)/(2-3x+x^(2)), :. x=0.64`
`:. [H_(2)]=1-0.6484=0.316 "mol" L^(-1) ( :' V=1L)`
`[I_(2)]=2-0.684=1.316 "mol" L^(-1)`
`[HI]=3+2(0.684)=4.368 "mol" L^(-1)`
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