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What is the % dissociation of H(2)S if 1...

What is the `%` dissociation of `H_(2)S` if `1` "mole" of `H_(2)S` is introduced into a `1.10 L` vessel at `1000 K`? `K_(c)` for the reaction
`2H_(2)S(g) hArr 2H_(2)(g)+S_(2)(g)` is `1xx10^(-6)`

Text Solution

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`{:(,2H_(2)S(g),hArr,2H_(2)(g),+,S_(2)(g)),("moles before dissociation",1,,0,,0),("moles after dissociation",(1-alpha),,alpha,,alpha//2):}`
wher `alpha` is the degree of dissociation of `H_(2)S`.
Volume of container `=1.10 L`
`:. K_(c )=([H_(2)]^(2)[S_(2)])/([H_(2)S]^(2))=([alpha/1.1]^(2)[alpha/(2xx1.1)])/([(1-alpha)/1.1]^(2))=1xx10^(-6)`
Assuming `1-alpha~~1`, since `alpha` is small because `K_(c)=10^(-6)`
`:. (alpha^(3))/(2(1.1))=10^(-6)rArr alpha=1.3xx10^(-2)=1.3%`
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