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Some solid NH(4)HS is placed in flask co...

Some solid `NH_(4)HS` is placed in flask containing `0.5` atm of `NH_(3)`. What would be the pressure of `NH_(3)` and `H_(2)S` when equilibrium is reached.
`NH_(4)HS(g) hArr NH_(3)(g)+H_(2)S(g), K_(p)=0.11`

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To solve the problem, we need to analyze the decomposition of solid ammonium hydrosulfide (NH₄HS) into ammonia (NH₃) and hydrogen sulfide (H₂S) gases. The equilibrium expression for the reaction is given, and we can use it to find the equilibrium pressures of NH₃ and H₂S. ### Step-by-Step Solution: 1. **Write the Reaction and Equilibrium Expression**: The decomposition of NH₄HS can be represented as: \[ \text{NH}_4\text{HS}(s) \rightleftharpoons \text{NH}_3(g) + \text{H}_2\text{S}(g) ...
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