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The equilibrium constant K(p) of the rea...

The equilibrium constant `K_(p)` of the reaction: `2SO_(2)+O_(2) hArr 2SO_(3)` is `900 atm^(-1)` at `800 K`. A mixture constaining `SO_(3)` and `O_(2)` having initial pressure of 1 atm and 2 atm respectively, is heated at constant volume to equilibriate. Calculate the partial pressure of each gas at `800 K` at equilibrium.

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To solve the problem, we need to find the partial pressures of each gas at equilibrium for the reaction: \[ 2SO_2 + O_2 \rightleftharpoons 2SO_3 \] Given: - The equilibrium constant \( K_p = 900 \, \text{atm}^{-1} \) at \( 800 \, K \). - Initial pressures: \( P_{SO_3} = 1 \, \text{atm} \) and \( P_{O_2} = 2 \, \text{atm} \). ...
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