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15 mol of H(2) and 5.2 moles of I(2) are...

`15` mol of `H_(2)` and `5.2` moles of `I_(2)` are mixed and allowed to attain eqilibrium at `500^(@)C` At equilibrium, the concentration of HI is founf to be `10` mol. The equilibrium constant for the formation of HI is.

A

`50`

B

`25`

C

`200`

D

`15`

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(,H_(2),+,I_(2),hArr,2HI),(t=0,15,,5.2,,0),(t_("Eq"),15-5,,5.2-5,,10):}`
`:. K_(c )=([HI]^(2))/([H_(2)][I_(2)])=100/(10xx0.2)=50`
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