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For the reaction: NOCl(g) hArr 2NO(g) +C...

For the reaction: `NOCl(g) hArr 2NO(g) +Cl_(2)(g), K_(c)` at `427^(@)C` is `3xx10^(6) L mol^(-1)`. The value of `K_(p)` is

A

`7.5`

B

`2.5xx10^(-5)`

C

`2.0xx10^(-4)`

D

`1.75xx10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
D

As `K_(p)=K_(c )(RT)^(Deltan)`
`Deltan=3-2=1`
`:. K_(p)=K_(c )(RT)`
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