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HI was heated in a sealed tube at 400^(@...

`HI` was heated in a sealed tube at `400^(@)C` till the equilibrium was reached. HI was found to be `22%` decomposed. The equilibrium constant for dissociation is

A

`1.99`

B

`0.0199`

C

`0.0796`

D

`0.282`

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(2HI,rarr,H_(2),+,I_(2)),(1,,0,,0),(1-x,,x/2,,x/2),(1-0.22=0.78,,0.11,,0.11):}`
`x=22%` of `1` mol `=22/100xx1=0.22`
`K=([H_(2)][I_(2)])/([HI])=(0.11xx0.11)/((0.78)^(2))=0.0199`
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