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K(c) for the reaction N(2)+3H(2) hArr 2N...

`K_(c)` for the reaction `N_(2)+3H_(2) hArr 2NH_(3)` is `0.5 mol^(-2) L^(2)` at `400 K`. Find `K_(p)`.
Given `R=0.082 L-"atm deg"^(-1) mol^(-1)`

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The correct Answer is:
A, C, D
`K_(P)=K_(C)(RT)^(Deltan)`
`:. K_(p)=0.5xx(0.082xx400)^(-2)`
`K_(p)=4.636xx10^(-4) ("atm")^(-2)`
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