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K(p) for 3//2H(2)+1//2N(2) hArr NH(3) ar...

`K_(p)` for `3//2H_(2)+1//2N_(2) hArr NH_(3)` are `0.0266` and `0.0129 atm^(-1)`, respectively, at `350^(@)C` and `400^(@)C`. Calculate the heat of formation of `NH_(3)`.

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The correct Answer is:
A, B, C, D
`2.303 "log"K_(p_(2))/K_(p_(1))=(DeltaH)/(R)[(T_(2)-T_(1))/(T_(1)T_(2))]`
`2.303"log"0.0129/0.0266=(DeltaH)/(2)[(673-623)/(673xx623)]`
`:. DeltaH=12140 cal=-12140 cal`
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