In a reaction at equilibrium, X moles of the reactant A decomposes to give `1` mole each of C and D. It has been found that the fraction of A decomposed at equilibrium is independent of initial concentration of A. Calculate X.

Answer

B

Explanation

`{:(XA,hArr,D,+,C),(a(1-alpha),,(aalpha)/x,,(aalpha)/x):}`
`:. K_(c)=(a^(2)alpha^(2))/(V^(2).x^(2)[(a(1-alpha))/V]^(x))=(a^(2).alpha^(2-x))/(x^(2)(1-alpha)^(x).V^(2-x))`
since `alpha` is independent of a `:. 2-x=0, x=2`