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The synthesis of ammonia is given as: ...

The synthesis of ammonia is given as:
`N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g), DeltaH^(ɵ)=-92.6 kJ mol^(-1)` given `K_(c)=1.2` and temperature `(T)=375^(@)C`
The expression of equilibrium constant is

A

`K_(c)=([N_(2)][H_(2)]^(3))/([NH_(3)]^(2))`

B

`K_(c)=([N_(2)][H_(2)])/([NH_(3)])`

C

`K_(c)=([NH_(3)])/([N_(2)][H_(2)]^(3))`

D

`K_(c)=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(c)=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))`
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