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N(2)(g)+3H(2)(g) hArr 2NH(3)(g), DeltaH^...

`N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g), DeltaH^(ɵ)=-22.4 kJ`
The pressure inside the chamber is `100` atm and temperature at `300 K`
If `K_(p)` for the given reaction is `1.44xx10^(-5)`, then the value of `K_(c)` will be:

A

`(1.44xx10^(-5))/((0.082xx500)^(-2)) mol L^(-1)`

B

`(1.44xx10^(-5))/((8.314xx200)^(-2)) mol L^(-1)`

C

`(1.44xx10^(-5))/((0.082xx700)^(2)) mol L^(-1)`

D

`(1.44xx10^(-5))/((0.082xx300)^(-2)) mol L^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
`K_(p)=K_(c)(RT)^(Deltan)=K_(c)(RT)^((2-4))`
`=K_(c)(RT)^(-2)=K_(c)/([(0.082)xx(300)]^(2))`
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