A reaction `S_(8)(g) hArr 4S_(2)(g)` is carried out by taking `2` mol of `S_(8)(g)` and `0.2` mol of `S_(2)(g)` is a reaction vessel of `1 L`. Which one is not correct if `K_(c)=6.30xx10^(-6)`

Options

A. Reaction qutient is `8xx10^(-4)`
B. Reaction proceed in backward direction.
C. Reaction proceed is forward direction
D. `K_(p)=2.55 atm^(3)`

Answer

A, B, D

Explanation

`Q=([S_(2)]^(4))/([S_(8)])=((0.2)^(4))/((2))=8xx10^(-4), K_(c)=6.3xx10^(-6)`
`:. K_(p)=K_(c)xx(RT)^(Deltan)=6.3xx10^(-6)xx(0.0821xx900)^(3)=2.55`
Thus, reaction proceed in backward direction since `Q gt K_(c)`