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van't Hoff equation is...

van't Hoff equation is

A

`(d//dT) ln K=-DeltaH//RT^(2)`

B

`d//dT (ln K)=+DeltaH//RT^(2)`

C

`(d//dT) ln K=-DeltaH//RT`

D

`K=Ae^(-DeltaH//RT)`

Text Solution

Verified by Experts

The correct Answer is:
B, D
The van't Hoff equation is `K=Ae^(-DeltaH//RT)`
or `(d ln K)/(delT)=(DeltaH)/(RT^(2))`
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What is van't Hoff equation for dilute solution?

Variation of K with temperature as given by van't Hoff equation can be written as

Knowledge Check

  • van't Hoff equation giving the effect of temperature on chemical equilibrium is represented as

    A
    `( dln F )/( dT) = ( Delta H )/( RT^(2))`
    B
    `( dln K_(p) )/( dT) = ( Delta HT^(2) )/( R)`
    C
    `( dln K_(p) )/( dT) = ( Delta H )/( RT^(2))`
    D
    `( dln K_(p) )/( dT) = ( Delta H T^(2))/( Delta H )`

  • According to van 't Hoff equation, K varies with temperature as:

    A
    `log ""K_(2)/K_(1)=(triangleH)/(2.303R) [1/T_(1)-1/T_(2)]`
    B
    `log ""K_(1)/K_(2)=+ (triangleH)/(2.303R) [1/T_(2)+1/T]`
    C
    `log ""K_(1)/K_(2)=-(triangleH)/(2.303R) [1/T_(2)+1/T_2]`
    D
    `log ""K_(2)/K_(1)=+ (triangleH)/(2.303R) [1/T_(1)+1/T_2]`

  • The expression for the reaction quotient , Q, is similar to that for equilibrim constant , Q, is similar to that for equilibrium constant K. The value of Q for the given composition of a reaction mixture helps us to know whether the reaction will move forward or backward or remain in equilibrium . It also helps to predict the effect of pressure on the direction of the gaseous reaction .In certain reactions, addition of inert gas also favours either the formation of reactants or products . The value of equilibrium constant of a reaction changes with change of temperature and the change is given by van't Hoff equation , d In K_(p)//dT = Delta H^(@)//RT^(2) where enthaply change, DeltaH^(@) , is taken as constant in the small temperature range. Which of the following will be correct ?

    A
    Plot of In `k_(p) " versus " 1//T^(2)` will be linear with + ve slope
    B
    Plot of In `K_(p) "verus" 1//T` will be linear with + vve slope
    C
    Plot of In `K_(p) " versus" 1//T^(2)` will be linear with -ve slope
    D
    Plot of In `K_(p) " versus " 1//T` will be linear with -ve slope

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    Variation of equilibrium constan K with temperature is given by van't Hoff equation InK=(Delta_(r)S^(@))/R-(Delta_(r)H^(@))/(RT) for this equation, (Delta_(r)H^(@)) can be evaluated if equilibrium constans K_(1) and K_(2) at two temperature T_(1) and T_(2) are known. log(K_(2)/K_(1))=(Delta_(r)H^(@))/(2.303R)[1/T_(1)-1/T_(2)] Select the correct statement :

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    What is van't Hoff reaction isotherm ?

    The reaction quotient, Q is expresse as some as, that for equilibrium constant K.The value of Q for the given composition of a reaction mixture helps us to know whether the reaction will move forward or backward or remain in equlibrium. It helphs to pedict the effect of pressure on the direction of the gaseous reaction. In some reactions, addition of inert gas also favours either the formation of reactansts or products. The value of equlibrium constant of a reaction changes with change of temperture and the change is gives by van't Hoff equation, d ln K_(p)//dT=DeltaH^(@)//RT^(2) where enthalpy change, DeltaH^(@), is taken as constant in the small temperatue range. Which of the following will be correct

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