The equilibrium constant for a reaction
`A+2B hArr 2C` is `40`. The equilibrium constant for reaction `C hArr B+1//2 A` is

Options

A. `1//40`
B. `(1//40)^(1//2)`
C. `(1//40)^(2)`
D. `40`

Answer

B

Explanation

`A+2B hArr 2C, " "`…(i) `K=40`
and for `" " c hArr B +1/2 A, " "` …(i) `K_(1)=?`
`K=1/sqrt(K)=1/((40)^(1//2))`
Since equation (2) is obtained by reversing and dividing by 2, the equation (1).