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When the reaction, 2NO(2)(g) hArr N(2)O(...

When the reaction, `2NO_(2)(g) hArr N_(2)O_(4)(g)` reaches equilibrium at `298 K`. The partial pressure of `NO_(2)` and `N_(2)O_(4)` are `0.2 Kpa` and `0.4 Kpa`, respectively. What is the equilibrium constant `K_(p)` of the above reaction at `298 K`?

A

`0.1`

B

`0.5`

C

`1.0`

D

`10`

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(,2NO_(2),hArr,N_(2)O_(4)),("At equilibrium",0.2 kPa,,0.4 kPa):}`
`K_(p)=([p_(N_(2)O_(4))])/([p_(NO_(2))])=0.4/(0.2xx0.2)=10`
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