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The equilibrium constant K(p) for a homo...

The equilibrium constant `K_(p)` for a homogeneous gaseous reaction is `10^(-8)`. The standard Gibbs free energy change `DeltaG^(ɵ)` for the reaction `("using" R=2 cal K^(-1) mol^(-1))` is

A

`10.98 kcal`

B

`-1.9 kcal`

C

`-4.1454 kcal`

D

`+4.1454 kcal`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaG^(ɵ)=-2.303 RT log K`
`=-2.303xx2xx298 log 10^(-8)`
`=-2.303xx2xx298xx-8 cal`
`=10980 cal=10.98 kcal`
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