In a chemical reaction
`N_(2)+3H_(2) hArr 2NH_(3)`, at equilibrium point

Options

A. Equal volumes of `N_(2)` and `H_(2)` are reacting
B. Equal masses of `N_(2)` and `H_(2)` are reacting
C. The reaction has stopped
D. The same amount of ammonia is formed as is decomposed into `N_(2)` and `H_(2)`

Answer

D

Explanation

At equilibrium, amount of `NH_(3)` formed is equal to the amount of `NH_(3)` decomposed into `H_(2)` and `N_(2)`.