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One mole of N(20O(4)(g) at 300K is kept ...

One mole of `N_(20O_(4)(g)` at 300K is kept in a closed container under one atmosphere. It is heated to 600K when 20% of `N_(2)O_(4)(g)` is converted to `NO_(2)(g)`
`N_(2)O_(4)hArr 2NO_(2)(g)` Hence resultant pressure is `:`

A

`1.2` atm

B

`2.4` atm

C

`2.0` atm

D

`1.0` atm

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(N_(2)O_(4),hArr,2NO_(2)),(1,,0),((1-0.2),,2xx0.2=0.4):}`
Total pressure `=1.2`
As the temperature is doubled, the pressure becomes double. Therefore, the total final pressure is `1.2xx2=2.4` atm.
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