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If the equilibrium constant for the reac...

If the equilibrium constant for the reaction
`A_(2)+B_(2) hArr 2AB`
is K, then the backward reaction,
`AB hArr 1/2 A_(2)+1/2 B_(2)`
the equilibrium constant is `1//K`.

Text Solution

Verified by Experts

False. If the equilibrium constant for the reaction
`AB hArr 1/2 A_(2)+1/2 B_(2)`
the equilibrium constant is `sqrt(1//K)` because the reaction is reversed as well as divided by two.
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