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The degree of dissociation is 0.4 at 400...

The degree of dissociation is `0.4` at `400 K` and `1.0` atm for the gaseous reaction
`PCl_(5) hArr PCl_(3)+Cl_(2)`
assuming ideal behaviour of all gases, calculate the density of equilibrium mixture at `400 K` and `1.0` atm (relative atomic mass of P is `31.0` and of Cl is `35.5`).

Text Solution

Verified by Experts

`{:(,PCl_(5)(g),hArr,PCl_(3)(g),+,Cl_(2)(g)),("Initial",1,,0,,0),("At equilibrium",(1-0.4),,0.4,,0.4):}`
Total moles at equilibrium is
`1-0.4+0.4+0.4=1.4`
`PV=nRT`
or `V=(nRT)/(P)=(1.4xx0.0821xx400)/(1)=45.976 L`
Density =`("Mass")/("Volume")`
`=208.5/45.976(("No change in mass"),("during reaction"))=4.54 g L^(-1)`
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