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A solution was made up by 0.01M Co(NO(3)...

A solution was made up by `0.01M Co(NO_(3))_(2)` and `.02 M N_(2)H_(4)` and was found to have at equilibrium `[Co^(2+)] = 0.0062M`. Calculate `K_(1)` for the complex formation of `Co(N_(2)H_(4))^(2+)`.

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`K_(1) = ([Co(N_(2)H_(4))^(2+)])/([Co^(2+)][N_(2)H_(4)]) = (0.0038)/((0.0062)(0.0162)) = 38`
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