`K_(a)` for `HA` is `4.9 xx 10^(-8)`. After making the necessary approximation, calculate for its decimolar solution,
a. `%` dissociation b. `overset(Θ)OH` concentration
c. `pH`

Explanation

`alpha = sqrt((K_(a)//C)) = sqrt(((4.9 xx 10^(-8)))/(1//10)) (C = (1)/(10)N or M)`
`= 7 xx 10^(-4) = 0.07% (K_(a) = 4.9 xx 10^(-8))`
`K_(a) = 4.9 xx 10^(-8) = 7 xx 10^(-4) = 0.07%`
`[H^(o+)] = Ca = 1//10 xx 7 xx 10^(-4) = 7 xx 10^(-5)`
`:. pH = 4.15 [overset(Θ)OH] [H^(o+)] = 10^(-14)`
`[overset(Θ)OH] = (10^(-14))/(7xx10^(-5)) = 1.43 xx 10^(-10)`