Three suggestion are made for ways to removes silver ions from solution:
a. Make the solution `0.01M`in `Nal`.
b. Buffer the solution at `pH = 13`.
c. Make the solution `0.01M Na_(2)S`. What will be the equilibrium silver ion concentartion in each case? which course of action is most effective in removing `Ag^(o+)` ions?
`K_(sp) (AgI) = 8.5 xx 10^(-17), K_(sp) (AgOH) = 2 xx 10^(-8)`,
`K_(sp) (Ag_(2)S) = 5.5 xx 10^(-51)`

Explanation

`Ag1 hArr Ag^(o+) + I^(Θ)`,
`AgOH hArr Ag^(o+) + overset(Θ)OH`
`Ag_(2)S hArr 2Ag^(o+) + S^(2-)`
a. `[Ag^(o+)] = (8.5 xx 10^(-17))/(10^(-2)) = 8.5 xx 10^(-15) M`
b. `pH = 13 :. [H^(o+)] = 10^(-13), [overset(Θ)OH] = 10^(-1)`
`[Ag^(o+)] = (2xx10^(-8))/(10^(-1)) = 2xx 10^(-7)M`
c. `[Ag^(o+)] = sqrt((5.5 xx 10^(-51))/(10^(-3))) = 2.345 xx 10^(-24) M`