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For the indicator 'Hin' the ratio (Ind^(...

For the indicator 'Hin' the ratio `(Ind^(Θ))//(HIn)` is `7.0` at `pH` of `4.3`. What is `K_(eq)` for the indicator.

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`pH = 4.3, [H^(o+)] = 5.0 xx 10^(-5)M`
`HIn hArr H^(o+) + In^(Θ)`
`K_(eq) = ([H^(o+)][Ind^(Θ)])/([HIn])`
`= (5.0 xx 10^(-5)) (7.0) = 3.5 xx 10^(-4)M`
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