It is found that `0.1M` solution of three sodium salts `NaX, NaY`, and `NaZ` have Ph 7.0, 9.0 and 11.0, respectively. Arrange the acids (HX, HY, and HZ) in order of increasing acidic character. Calculate dissociation constant of acids.

Explanation

`{:(NaX+H_(2)Orarr"No hydrolysis",,"bacause",pH =7.0,),(NaY+H_(2)OrarrNaOH+HY,,,pH=9.0,),(NaZ+H_(2)OrarrNaOH+HZ,,,pH=11.0,):}`
Thus, acidic character order for acids is : `HX gt HY gt HZ`
Also for `NaY, [overset(Theta)OH] = 10^(-5) because pH = 9 :. pOH = 5`
`Ch 10^(-5)`
`C.sqrt((K_(h))/(c)) = 10^(-5)` or `C.sqrt((K_(h)xxC)/(K_(a))) = 10^(-5)`
`(10^(-14)xx0.1)/(K_(a)) = 10^(-10), :. K_(a)` for `HY = 10^(-5)`
Similarly, `K_(a) for HZ = 10^(-9)`