Calculate the `pH` of solution obtained by mixing `10 ml` of `0.1 M HCl` and `40 ml` of `0.2 M H_(2)SO_(4)`

Answer

D

Explanation

Milli equivalent of `H^(o+)` from `HC1 = 10 xx 0.1 = 1`
Milli equivalent of `H^(o+)` from `H_(2)SO_(4) = 40 xx 0.2 xx2 = 16`
`:.` Total `mEq` of `H^(o+)` in solution `= 1 + 16 = 17`
`:. [H^(o+)] = (17)/(50) = 3.4 xx 10^(-1) (because [H^(o+)] = (mEq)/(V_("in mL")))`
`:. pH =- log [H^(o+)] =- log (0.34)`
`pH = 0.4685`