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Find the dissocation constant K(a) of HA...

Find the dissocation constant `K_(a)` of `HA` (weak monoabsic acid) which is `3.5%` dissociated in an`M//20` solution.

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The correct Answer is:
A, C
`K_(a) = (C alpha^(2))/(1-alpha) (a = 3.5% = (3.5)/(100) = 0.035)`
`= (1)/(20) xx ((0.035)^(2))/((1.0-0.035)) = 6.35 xx 10^(-5)`
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