For a 'C'`M` concentarted solution of a weak electrolyte `A_(x)B_(y)alpha`(degree of dissociation) is

Options

A. `sqrt(K_(eq)//xyC)`
B. `[K_(eq).C//(xy)]^(1//2)`
C. `(K_(eq)//C^(x+y-1).x^(x)x^(y))^((1)/(x+y))`
D. `[K_(eq)//C(x+y)]^(1//2)`

Answer

C

Explanation

`{:(A_(x)B_(y)hArr,xA^(+y),+,yB^(-x),),(1,0,,0,),(C(1-alpha),x.Calpha,,y.Calpha,):}`
`K_(a) = ((x.Calpha)^(x)(y.Calpha)^(y))/(C(1-alpha))`
(Assuming `1-alpha ~~1)`
`K_(a) = (x^(x).y^(y).C^(x+y).alpha^(x+y))/(c)`
`K_(a) = x^(x)y^(y).C^(x+y-1).alpha^(x+y)`
`:. alpha^(x+y) = (K_(a))/(x^(x).y^(y).C^(x+y-1))`
`:. alpha=((K_(a))/(x^(x).y^(y).X^(x+y-1)))^((1)/(x+y))`