The percentage error in `[H^(o+)]` provided by `10^(-8)M HC1`, if ionisation of water is not neglected, is

Options

A. `2%`
B. `3%`
C. `4%`
D. `5%`

Answer

D

Explanation

`10^(-8) M HC1`:
a. `[H^(o+)] = 10^(-8) = 10 xx 10^(-9)`
(if dissociation of water is neglected)
b. If dissociation of water is not neglected:
`{:(H_(2)OhArr,H^(o+),+,overset(Theta)OH,),(,a+10^(-8),,a,):}`
`a(a + 10^(-8)) = 10^(-14)`
`a = 0.95 xx 10^(-7)`
`:.` % error =
`= ((10xx10^(-9)-9.5xx10^(-9))/(10xx10^(-9))) xx 100 = 5%`