Calcualte the percentage hydrolysis of `10^(-3)M N_(2)^(o+)H_(5)C1^(Theta)` (hydrazinium chloride), salt contining acid ion conjugate to hydrazine base `(NH_(2)NH_(2)). K_(b)` for `N_(2)H_(4) = 1.0 xx 10^(-6)`.

Answer

B, C

Explanation

`[N_(2)^(o+)H_(5)]C1^(Theta)` is a salt of `W_(B)//S_(A)`.
`K_(h) = (K_(w))/(K_(b)) = (10^(-14))/(10^(-6)) = 10^(-8)`
`K_(h) = sqrt((K_(h))/(c)) = ((10^(-8))/(10^(-3)))^(1//2) = (10^(-5))^((1)/(2))`
`= (10 xx 10^(-6))^(1//2)`
`= sqrt(10) xx 10^(-3)`
`= 3.162 xx 10^(-3)`
`%h = 3.16 xx 10^(-3) xx 100`
`= 0.316 ~~ 0.32%`